74b^2=16

Solution for 74b^2=16 equation:

74b^2=16

We move all terms to the left:

74b^2-(16)=0

a = 74; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·74·(-16)
Δ = 4736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4736}=\sqrt{64*74}=\sqrt{64}*\sqrt{74}=8\sqrt{74}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{74}}{2*74}=\frac{0-8\sqrt{74}}{148}
=-\frac{8\sqrt{74}}{148}
=-\frac{2\sqrt{74}}{37}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{74}}{2*74}=\frac{0+8\sqrt{74}}{148}
=\frac{8\sqrt{74}}{148}
=\frac{2\sqrt{74}}{37}
$